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@binks
Looks like you can assume it's a square, so AB and CD are equal to each other. So put 32= 2/3x - 10 and solve.
2/3x-10=32 multiply 2/3 by x 2x/3 2x/3 - 10-32 -10 does not contain the variable to solve so move it to the right side of the equation adding 10 to both sides 2x/3=10+32 Add 32 to 10 = 42 2x/3=42 multiply both sides by three multiply 42 by 3 2x=126 divide by 2 2x/2 = 126/2 x=126/2 divide x=63
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