Write the quadratic function in standard form.
y= -(x+2)^2-7

Question

Write the quadratic function in standard form. 
y= -(x+2)^2-7

whpalmer4 · Answer

standard form is 
y = ax^2 + bx + c

so, you need to expand that (x+2)^2 bit and arrange the results accordingly

anonymous · Answer

What do you do with the exponent 2?

whpalmer4 · Answer

(x+2)(x+2) = x*2 + 2*x + 2*x + 2*2 = x^2 + 4x + 4
so y = -(x+2)^2 - 7 = - (x^2 + 4x + 4) - 7  = -x^2 - 4x - 4 - 7 = -x^2 - 4x - 11

@eliassaab got to watch for those leading - signs :-)

anonymous · Answer

$$(x+2)^2= x^2 + 4 x +4\
y=-(x+2)^2-7= -x^2 -4 x -4-7=  x^2 + 4 x -3\
y=  -x^2- 4 x -11

$$

anonymous · Answer

@whpalmer4, thanks for you remark. I am getting old to see the minus sign.