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OpenStudy (ttop0816):
Please help! Solve for x for 180° < x < 270°. sin^2(x) = 1/4
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OpenStudy (linknissan):
Ok Let me help! 180-270.. Andle is in the third quadrant.. Right? Waht is the sign of X and Y quadrant in 3rd Quarant?
OpenStudy (linknissan):
Angle*
OpenStudy (lncognlto):
Maybe this will help: http://image.tutorvista.com/contentimages/maths/content/us/class11maths/chapter08/images/img668.gif
OpenStudy (lncognlto):
sin^2(x) = 1/4 therefore sin (x) = square root (1/4) Therefore sin (x) = (-1/2) or (1/2)
OpenStudy (ttop0816):
so what would the degree be??
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