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Find cot θ if csc θ -(sqrt 37)/6
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you know that cotx is cosx/sinx and you know that cosecx is 1/sinx so knowing that, you should be able to do it
would it be 1/6
or just sqrt of 37
please help me
look at the formula sin^2x+cos^2x=1 if you work from that you end up getting 1+cot^2x=cosec^2 cot^2x=cosec^2-1 square root both sides gives cotx
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jzamora, I didn't realize you had left our unfinished discussion. Perhaps you can find others to help you instead of me.
ok so how would i go on?
To get cot^2x you need to find what Cosec^2x -1 is work out cosec^2x by squaring the value you are given subtract 1 then square root to get 2 answers
ok so i got 6? is that right?
i don't think its right
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1/6
is correct
ok thank you very much
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