Question

HELPPPPP D;

Answer 1

HOLD ON

Answer 2

one second.

Answer 3

;D okay!

Answer 4

ok, had to review for a second.

Answer 5

Oh,I have this like chart thingy with the standard forms of equations for hyperbolas,do you want to see it?

Answer 6

nah I have it. I'm writing it out, but it's a long problem. =)

Answer 7

Does this make sense so far? https://drive.google.com/a/gsd.wednet.edu/file/d/0B5q8dbsgquFmdEdjaUF2OExBRHc/edit?usp=sharing

Answer 8

Hold on!

Answer 9

They need to add a feature for quick google hangout for these pre-calc problems

Answer 10

I need permission from you!

Answer 11

oops sorry about that: https://drive.google.com/a/gsd.wednet.edu/#my-drive

Answer 12

ugh, ok, one more time: https://drive.google.com/file/d/0B5q8dbsgquFmdEdjaUF2OExBRHc/edit?usp=sharing

Answer 13

Okay,this makes sense!

Answer 14

oooookay. https://drive.google.com/file/d/0B5q8dbsgquFmd0szQ0RJUU90TEE/edit?usp=sharing

Answer 15

Okay!

Answer 16

It's really tedious at first, but then you get used to it.

Answer 17

Yes! I know smh, thank you so much! ;') I really appreciate your help!!!

Answer 18

I assume you need help on the second one too? =)

Answer 19

xD Yes

Answer 20

lol, don't you guys have a tutor lab over there?

Answer 21

ok, let me draw it out.

Answer 22

No xD
we have to request a tutor session which ends up being harder than you think

Answer 23

ok I got it.

Answer 24

https://drive.google.com/file/d/0B5q8dbsgquFmZXBwWk40UkJKc2s/edit?usp=sharing

Answer 25

OK!

Answer 26

https://drive.google.com/file/d/0B5q8dbsgquFmbktMQU5zckJ5Vlk/edit?usp=sharing

Answer 27

Oh wow,that one seemed easier, THANK YOU ;D!!!

Answer 28

I graphed my answer, so I'm pretty sure it's right.

Answer 29

And can you help me with one more? I started it but cant finish it
It gives me an equation then I have to graph it

Answer 30

hold on!

Answer 31

THIS ONE? D';

Answer 32

@mary.rojas ok.

Answer 33

Is goal to graph it?

Answer 34

yes!

Answer 35

Ok, one second.

Answer 36

okay!

Answer 37

Hopefully this makes sense: https://drive.google.com/file/d/0B5q8dbsgquFmbV9HaG1raU9odlU/edit?usp=sharing

Answer 38

https://drive.google.com/file/d/0B5q8dbsgquFmUTVyMGNQdEtCVTg/edit?usp=sharing

Answer 39

Okay thanks!
Can you just check over my work for these? 2 more problems?

Answer 40

Am stumped on the second one :(

Answer 41

hold on

Answer 42

@jbell0385

Answer 43

hmmm never heard of eccentricity.

Answer 44

looking it up.

Answer 45

Eccentricity= c/a

Answer 46

according to my math teacher...

Answer 47

https://drive.google.com/file/d/0B5q8dbsgquFmbWpaUmJUNVBONm8/edit?usp=sharing

Answer 48

^that's right, e = c/a

Answer 49

That's what I got for the first problem. I'm not sure what's going on in the second problem. =)

Answer 50

:)
and for he second one.....smh am using the "compete the square" method to get the equation to standard form...but I cant reduce that cleanly so am doubting my work
and after I get that in standard form,I could point out c and a

Answer 51

-2y^2 + 24y does not equal -2(y^2 + 6y) :P

-2y^2 + 24y = -2(y^2 - 12y)

Answer 52

Oh darn,smh thank you so much! @agent0smith