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OpenStudy (anonymous):

What is the formula for max height?

OpenStudy (anonymous):

of what?

OpenStudy (anonymous):

im guessing projectile motion y = Vit - 1/2 g t^2 V = Vi - gt at max height this is 0 so t = Vi/g replacing this into the original y = Vi^2/g - 1/2 Vi^2/g y = (1/2)Vi^2/g .... i think :)

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