Question

y=3x^2-6x+4 Can someone help me graph the parabola,find its vertex, x and y intercept

Answer 1

Don't remember all the steps? =)

Answer 2

The vertex i think i got it....(-1,7)

Answer 3

almost

Answer 4

x: -b/2a The b is already negative, so since b is (-6), then it makes it positive.

Answer 5

-9

Answer 6

So the vertex is -9,185 ??????

Answer 7

mmm. ok, hold on.

Answer 8

okay

Answer 9

its a -3 not a postive 3

Answer 10

oh ok, that changes some things.

Answer 11

now what..how do i find the x and y axis

Answer 12

when x = 0 what is y?
when y = 0 what is x?
y = ax^2 + bx + c
identify a, b and c in this eqn 3x^2 -6x +4
vertex = -b/2a
when a >= 0 it opens up; when a < 0 it turns down
for this eqn is a >=0 or <0
use the points to sketch the graph