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Solve, using linear combination: 4x + y = 5 3x + y = 3 A: (0, –3) B: (0, 5) C: (2, –3) D: (–3, 7)
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eqn 1 subtract eqn 2 to eliminate y solve for x substitute in either eqn to find y
x = 2 option c check y anyway 4(x) + y =5 4(2) +y =5 8 + y =5 y =
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