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OpenStudy (anonymous):
In isosceles triangle ABC, AB=AC and BC=300. Let D be a point on AB such that DE is perpendicular to AC. If DE=120, DB=221 and CE=271, find AD.
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OpenStudy (nikato):
|dw:1390719440962:dw|
OpenStudy (nikato):
where would u put DE, specificly where would E be?
OpenStudy (anonymous):
@nikato Let D be a point on AB and E a point on AC such that DE is perpendicular to AC
OpenStudy (nikato):
ok. thanks. thats much clearer
OpenStudy (nikato):
is there any more info?
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OpenStudy (anonymous):
@nikato That's all that is written here.
OpenStudy (nikato):
wait a moment. still working...
OpenStudy (anonymous):
@nikato Okay, I will wait for your reply :)
OpenStudy (nikato):
ok. is what i got so far..|dw:1390720956701:dw|
OpenStudy (nikato):
and u can set up these two equations
221+x=271+y
120^2 +y^2=x^2
but somehow this doesnt really work
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OpenStudy (nikato):
@agent0smith can u help with this problem please?
OpenStudy (anonymous):
@nikato If it helps, the answer is 169. I'm just looking for how to solve this problem.
OpenStudy (mathstudent55):
|dw:1390722146884:dw|
OpenStudy (mathstudent55):
|dw:1390723644629:dw|
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