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OpenStudy (anonymous):
log 5x = log (2x+9)
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OpenStudy (anonymous):
U know the answer or what??
OpenStudy (cggurumanjunath):
on taking antilog on both sides. 5x=(2x+9) now solve for x
OpenStudy (mathstudent55):
\( \log a = \log b \iff a = b\)
OpenStudy (anonymous):
log gets cancelled on both sides.. 5x=2x+9 5x-2x=9 3x=9 x=3
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