help please i got first part of question i am stuck on second part see attached
found height as 8.7sqrt3
@ranga or @e.mccormick
i know as well area for trapezoid is 1/2h(b1+b2)
@hartnn
answer in book is A=489.7cm^2
AI=17.4cos 60=17.4*1/2=8.7 AD=8.7+31.8=40.5 area=(40.5+24.5)/2*8.7sqrt3
i am in just geometry now so i dont know sin or cos yet
ok, so you can find AI using pythagoras theorem
you have h = 8.7 sqrt 3 b1 = 24.5 you need b2 = 31.8 + AI
How you calculated h ?
sqrt3/2*17.4 = h
good, you used the fact that side opposite to 60 degree angle is sqrt 3 /2 times the hypotenuse to find AI, you can use the fact that side opposite ti 30 degree angle is half the hypotenuse
?? so 8.7 sqrt 3/2?
oh i get it so 17.4/2 :)
but hypotenuse is 17.4 so AI = 17.4/2 yes! :)
so now add 8.7 to the 31.8 to get 40.5 then i got it and plug into the 1/2h(b1+b2) :D
you got it :D
thanks geometry is new to me - still trying to understand it all kinda trippy lol
with some practice, you'll love geometry :)
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