Question

A population has only 2 alleles, F for individuals with freckles and f for individuals without. The allele frequency of F is 58%. What are the genotype frequencies of the population assuming all 5 of the hardy winebergy conditions are met. I got P=33% Pq=49% and q=18% did I do it right?

Answer 1

@wolfe8

Answer 2

Wait what are P, Pq, and q?

Answer 3

P is the homozygous dominant. pq is the heterozygous and q is the homozygous recessive. Together they create the hardy Weinberg equation. P^2 +2pq+q^2

Answer 4

I'm so sorry I never did this before. I found this: http://en.wikipedia.org/wiki/Allele_frequency But I'm guessing you did it right.

Answer 5

thanks. :)

Answer 6

You did it correctly