Question

1. Tony and Belinda have a combined age of 56. Belinda is 8 more than twice Tony’s age. How old is each?

Answer 1

t+b=56
b=2t+8

Answer 2

what do u do next?

Answer 3

Solve that system

Answer 4

Use substitution by replacing b in the first equation with 2t+8 from the second equation.

Answer 5

t+b=56, <equation 1
b-8=2t <equation 2
so now solve - i will solve by substitution
t=56-b sub:
b-8=2t
b-8=2(56-b)
b-8=112-2b
b+2b=120
3b=120
b=40, so belinda is 40, sub to find tony's age
t+b=56
t=56-40
t=16
therefore, tony is 16 and belinda is 40. i think this is the answer

Answer 6

@dg98 Thank You!!