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Mathematics 8 Online
OpenStudy (ttop0816):

Find cotθ if θ terminates in Quadrant III and secθ = 2. sq.root 3 << am i correct?? -sq.root3/3 sq.root3/3 -sq.root3

OpenStudy (anonymous):

secant cant be 2 in quadrant 3. the x value will be negative.

OpenStudy (ttop0816):

ohh so it would be -sq.root3??

OpenStudy (anonymous):

no, the question you posted is invalid.

OpenStudy (anonymous):

but if the 2 was negative the answer would be sqrt3/3 do you understand how i got that? this is a 30 60 90 special triangle. since sec -2 is 240 degrees

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