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someone please factor this completely 6(x+5)^2-5(x+5)+1
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[(3(x+5)-1][2(x+5)-1]
Can you show me step by step how you did it please?
Could you factor this: 6a^2-5a+1
ya i got (1 + -3a)(1 + -2a) is that right?
Yes or more typically (3a-1)(2a-1)
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oh ok. so how did you get that expression i asked?
would you mind checking my other factoring questions i answered because I am not sure if its right?
Now, notice your problem is exactly the same as the one you just factored. Just replace each a with (x+5)
replace it where?
6 a^2 -5 a +1 = (3 a - 1)(2 a - 1) 6(x+5)^2-5(x+5) +1 = (3(x+5)-1)(2(x+5) -1 )
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Do you see how the two problems are exactly the same?
oh yes i do
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