Question

using the circle, find the value of x to the nearest tenth.

Answer 1

picture?

Answer 2

attaching one now

Answer 3

Okay, so you the Pythagorean theorem. a^2 + b^2 = c^2, where c = hypotenuse

Hypotenuse = 7 + x
side a = x
side b = 10

Plug in...

(x)^2 + (10)^2 = (7 + x)^2

Solve for x. :)

Answer 4

x^2+100=49+x^2

Answer 5

um, not quite.
(7 + x)^2 = (7+x)(7 + x)

Answer 6

oh ok

Answer 7

a^2+100=49+14x+x^2

Answer 8

good, now keep going, tho a^2 would be x^2

Answer 9

x^2+51=14x+x^2

Answer 10

good, keep going

Answer 11

x^2/x^2+51=14x+x^2/x^2

51/14=14x/14

x=3.6

Answer 12

great work!

Answer 13

thanks for the help

Answer 14

you're welcome