3(a+c)=d-e
Whats the question? it doesnt make sence
You are supposed to solve and find the restriction.
solve for what? what is the unknown here
But i cant if there is no question ........................................................................... soooo yeah
they all are unknown lol
3(a+c) = 3a+3c
Solve for C
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Its freaking ALLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL wrong
3a+3c=d-e -3a -3a 3c = d-e-3a divide both sides by 3 c = (1/3)(-3a+d-e)
Simply it further
But whats the restriction of that problem?
So your saying its like 3d 3r? but... ok i dont get it
c = ((d-e)/3)-a
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3(a+c)=d-e sooo solve for c and find the restriction that's the problem
that's as simple as gets
Theres supposed to be a restriction too
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TELL ME -_- NOW
if you let d or e = 0, it is still not going to be undefined.
I don't see any restriction.
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Okay thank you so much!
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