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Condense to a single logarithm. logv3x+logv3y+4logv3^z
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u can use log a + log b = log (a*b) to simplify
oh also a*(log b) = log (b^a)
what would that look like? I'm not sure where the numbers plug into the equation
u got logv3x+logv3y and i show log a + log b = log (a*b) so a=x and b=3y...
ooops typo i mean a=3x n b=3y
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