Question

one number is 2 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 416, find the numbers?

Answer 1

2n+100=416 I believe that is you're equation

Answer 2

actually the first number is n, the second 2n, and the third n+100
so when you add the three numbers you get the equation n+2n+n+100=416

Answer 3

first number = n
second number = 2n
third number = n + 100
(n) + (2n) + (n + 100) = 416 --- combine like terms
4n + 100 = 416 --- subtract 100 from both sides
4n = 416 - 100
4n = 316 --- divide both sides by 4
n = 316/4
n = 79

2n = 2(79) = 158

n + 100 = 79 + 100 = 179

your numbers are : 79,158, and 179