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what are the coordinates of the vertex of y = x^2 - 2x - 7 (-1, -7) (-1, -4) (1, -8) (1, -7)
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The simplest way is to find the point where the derivative of the function f(x) = y is zero. The derivative is f'(x) = 2x - 2. Set this to zero and solve for x.
sooo....-1,-4?
how can it be -1? try again. 2x-2 = 0
1,-8
correct!
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