Question

(x–3)^2–81=0

Answer 1

are you trying to solve for x?

Answer 2

if you add 81 to each side of the equation, you get

(x-3)^2 = 81

do you know any numbers that when squared equal 81?

Answer 3

(don't forget that there's a negative number which when squared equals 81, too)

Answer 4

10*10 = 100. 10 is too big
7*7 = 49. 7 is too small
must be somewhere between 7 and 10, don't you think?

Answer 5

just take the square root of both sides so then you get:
x-3= +/- 9
so then you add 3+9 and 3+ (-9)
sooooo answers are x= 12 and -6

Answer 6

(x–3)^2–81=0
(x–3)^2=81
x–3=+-sqrt(81)
x=+-sqrt(81)+3

x = 3-9 = -6
x = 9+3 = 12