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Solve the differential equation :- (y+3x^2)dy/dx=x
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y=ux2 dy=x2du+2xudx
You sure? :/ So you too y as ux^2, eh?
actually u=y/x2 is a two variable function to solve the de
Hm, that's perfectly fine.. It's just, i don't get the answer :(
ok just put the new variable u instead y then you reach the answer.
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(ux2+3x2)(x2du+2xudx)=xdx
(u+3)x4du+2(u+3)x3udx=xdx
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