Question

Check me please?

For the function g(x)=2x^2+1/x+3, what value of x makes this function undefined?

I think it's 2.

Write the quatiton of the vertical asymptote defined by this value of x.

Is it: x=-3?

Answer 1

A function is undefined when the denominator is 0.

So since the denominator is x+3, equate it to 0.
x+3=0
x=-3
When x=-3, the denominator becomes zero making the function undefined.

Answer 2

Yes, the vertical asymptote is x=-3.