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Mathematics 18 Online
OpenStudy (anonymous):

Can someone explain.....Find the difference ?

OpenStudy (anonymous):

4ab^2 -3ab^2

OpenStudy (cggurumanjunath):

ab^2(4-3)

OpenStudy (cggurumanjunath):

4*a*b^2-3*a*b^2=(4-3)*a*b^2

OpenStudy (cggurumanjunath):

a*b^2 is common in both the terms !

OpenStudy (anonymous):

ab^2

OpenStudy (cggurumanjunath):

yes

OpenStudy (cggurumanjunath):

so we take out ab^2 in both the terms and write the given problem as 4*a*b^2-3*a*b^2=(4-3)*a*b^2

OpenStudy (cggurumanjunath):

ab^2 (4-3)=4ab^2 -3ab^2

OpenStudy (anonymous):

would it be ab^4 or woud it be ab^2 ?

OpenStudy (anonymous):

@CGGURUMANJUNATH

OpenStudy (cggurumanjunath):

ab^2

OpenStudy (anonymous):

thanks for the explaination bro

OpenStudy (cggurumanjunath):

assume it like this !

OpenStudy (cggurumanjunath):

4ab^2-3ab^2=4*a*b*b-3*a*b*b=a*b*b(4-3)

OpenStudy (cggurumanjunath):

4ab^2-3ab^2=4*a*b*b-3*a*b*b=a*b*b(4-3)=a*b*b=ab^2 because 4-3 =1

OpenStudy (anonymous):

3x^y - x^2y find the difference.

OpenStudy (cggurumanjunath):

can u post the image of the question ?

OpenStudy (anonymous):

ya one second

OpenStudy (anonymous):

OpenStudy (cggurumanjunath):

can u tell me the answer ? @JC9977002

OpenStudy (anonymous):

no its a pre test i'm just trying to get a brief introduction on what i'm learning throughout this course.

OpenStudy (cggurumanjunath):

3*x^2y-x^2y=3*x*x*y-x*x*y=x*x*y*(3-1)

OpenStudy (anonymous):

so it equals 2 right ?

OpenStudy (cggurumanjunath):

x*x*y*(3-1) =?

OpenStudy (anonymous):

?=2 ?

OpenStudy (cggurumanjunath):

x*x*y*(3-1) =x*x*y* (2) !

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