For the polynomial equation:

x^3-7x^2-x+7=0

I found that the possible roots that produce a remainder of 0 are 1 and 7.

How would you write the resulting quadratic function and how would you factor or use the quadratic formula to find the final two roots?

Question

For the polynomial equation:

x^3-7x^2-x+7=0

I found that the possible roots that produce a remainder of 0 are 1 and 7.

How would you write the resulting quadratic function and how would you factor or use the quadratic formula to find the final two roots?

anonymous · Answer

$$x ^{2} (x-7) -x+7=0$$
$$(x ^{2}-1)(x-7)=0$$

then the roots are 1, -1 and 7 .