Question

For the polynomial equation:

x^3-7x^2-x+7=0

I found that the possible roots that produce a remainder of 0 are 1 and 7.

How would you write the resulting quadratic function and how would you factor or use the quadratic formula to find the final two roots?

Answer 1

\[x ^{2} (x-7) -x+7=0\]
\[(x ^{2}-1)(x-7)=0\]

then the roots are 1, -1 and 7 .