Two 0.9mL aliquots of the same specimen are placed in test tubes. To one is added 0.1 mL of water (spec A). To the other is added 0.1 mL of 200 mg/dl urea (spec B). They are analyzed for their results: Spec A: 25 mg/dl, Spec B: 43 mg/dl. What is the percent recovery of this method?

Question

petiteme · Answer

How do you solve it?

anonymous · Answer

im not sure... thats my question ... i know the formula is %recovery = amount of pure product recovered / amount of crude material used ... but idk how to manipulate the information given