Question

Can anybody help me solve this extraneous solution?

Answer 1

@zepdrix

Answer 2

(7x+6)^(1/2) - (9+4x)^(1/2) = 0


sqrt(7x+6) - sqrt(9+4x) = 0


sqrt(7x+6) = sqrt(9+4x)


7x+6 = 9+4x


...
...
...


x = ???

Answer 3

combine the like terms?

Answer 4

you have to get the like terms to the same side first

Answer 5

7x+4x=6+9=0

Answer 6

7x+6 = 9+4x

7x-4x = 9-6

Answer 7

3x=3, x=1

Answer 8

is that correct

Answer 9

x = 1 is correct

Answer 10

(x+5)^(1/2) - (5-2x)^(1/4) = 0

(x+5)^(1/2) = (5-2x)^(1/4)

x+5 = (5-2x)^(1/2) ... square both sides

(x+5)^2 = 5-2x ... square both sides again

x^2 + 10x + 25 = 5 - 2x

I'll let you take over

Answer 11

x^2+12x+20
(x+10)(X+2)

Answer 12

good, keep going and make sure to check each possible solution