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Mathematics 11 Online
OpenStudy (anonymous):

CAN SOMEONE PLEASE CHECK ME?! Combine the exponential expressions to produce a single exponential expression: e^x e^(x+1)=1 I got 2e^2+1=1, is that correct?

OpenStudy (anonymous):

wouldn't it be e^(2x+1)=1

OpenStudy (anonymous):

It probably would be! Thank you! Do you by chance know how to convert the original expression into a logarithmic equation? @ChrisTopher987654321

OpenStudy (anonymous):

log e (1)=2x+1 Probably too late but here you go.

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