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OpenStudy (anonymous):
How do you find the length of the focal chord for: y^2+6y-2x+13=0 ?
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OpenStudy (mertsj):
put it into the form y^2=4px 4p is the length of the focal chord.
OpenStudy (anonymous):
I got 1, is that right? @Mertsj
OpenStudy (mertsj):
I got 2
OpenStudy (mertsj):
y^2+6y+13=2x (y+3)^2=2x-4 (y+3)^2=2(x-4) 4p=2
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