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Mathematics 16 Online
OpenStudy (anonymous):

Polar Company has designed an ice block in the shape of a cube. The volume of the cube is 15 625 cm3. Which of the following dimensions is the smallest opening of an ice dispenser that will accommodate length AB?

OpenStudy (anonymous):

answers are 25, 40, 45, or 50 cm wide

OpenStudy (doc.brown):

A cube has the same length in all three dimensions. A cube 3 by 3 by 3 has a volume of 3 times 3 times 3. So what times what times what is 15625?

OpenStudy (anonymous):

I already know the cube root of 15 625 is 25

OpenStudy (doc.brown):

Then you get the medal.

OpenStudy (anonymous):

oh yeah you need the picture... sorry. A-B is from opposite corners

OpenStudy (doc.brown):

lol oh

OpenStudy (mathstudent55):

I can explain how to find length AB, but since the draw tool isn't working, can you put up the same figure but with all vertices labeled?

OpenStudy (doc.brown):

Draw a line from A to the top right corner. You can find that length using Pythagoras. Then A, top corner, B form another right angle triangle. Pythagorean again for the answer

OpenStudy (anonymous):

not sure how do to that...

OpenStudy (anonymous):

I know what pythagorean theorem is but how would I apply that to a three dimentional triangle?

OpenStudy (doc.brown):

No such thing as a three dimensional triangle, if you're only talking about magnitudes (lengths).

OpenStudy (mathstudent55):

B--------------D /I / I / I / I / I / I / I / I C--+-----------E I I I I I I G----------+--- I F I / I / I / I / I/ I/ H--------------A

OpenStudy (mathstudent55):

Ok, there's a cube.

OpenStudy (doc.brown):

YEAH!! GOOD PICTURE!!

OpenStudy (anonymous):

dude... nice ASCII art!

OpenStudy (mathstudent55):

You need the distance from A to B, opposite vertices. Use the Pythagorean theorem twice. First using lengths AH and GH, find GA. AH and GH are both 25 cm. Once you know GA, use GA and BG to find AB.

OpenStudy (mathstudent55):

Thanks. I guess I used the only tool left since the draw tool isn't working.

OpenStudy (anonymous):

Thanks!

OpenStudy (doc.brown):

Wait... |AG|^2 = |AH|^2 + |CH|^2 |AB|^2 = |AG|^2 + |BG|^2 substitute |AB|^2 = |AH|^2 + |CH|^2 + |BG|^2 AB = sqrt(25^2 + 25^2 + 25^2)

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