Question

(f(10+h)-f(10))/h

can be written as:
-1/A(B+h)

Where are A and B constants?

F(X)=1/(x+2)

Answer 1

If this helps:

A=?
B=?

Answer 2

F(X)=1/(x+2)
F(x+h)=1/(x+2+h)
(F(x+h)-F(x))/h=1/h [1/(x+2+h)-1/(x+2)]=(x+2-x-2-h)/ h(x+2)(x+2+h)=-1/(x+2)(x+2+h)