Question

Find the solution to the differential equation that satisfies the initial conditions y(0)=50

Answer 1

where is the differential equation?

Answer 2

dy/dt=ky

Answer 3

k is a constant

Answer 4

hmmm separable equation?

Answer 5

1/y dy = k dt...
ln y = k t
y = e^kt ?

Answer 6

how do you include the initial condition?

Answer 7

it's been a year since my calculus ab course and now i'm in physics c :/

Answer 8

Y(0) = 50 soo the ??
50 = e^k(0) ???

Answer 9

that doesn't look right ... that's 1 = 50 nooooo

Answer 10

ln y = k t

Answer 11

e^lny = e^kt djfslakjdaljfd

Answer 12

would it be y=50e^k*t then
100=50e^k*5
so k=0.1386
y=50e^90.1386)8t??

Answer 13

that 8 should be *

Answer 14

y+50e^(0.1386)*t