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Mathematics 24 Online
OpenStudy (anonymous):

x^3+8

jimthompson5910 (jim_thompson5910):

If you want to factor this, use the sum of cubes factoring rule a^3 + b^3 = (a+b)(a^2 - ab + b^2)

jimthompson5910 (jim_thompson5910):

notice how 8 = 2^3 so we can write x^3+8 as x^3 + 2^3

jimthompson5910 (jim_thompson5910):

tell me what you get

OpenStudy (anonymous):

x^2-4x+4

jimthompson5910 (jim_thompson5910):

is this a new problem?

OpenStudy (anonymous):

no thats the answer

jimthompson5910 (jim_thompson5910):

not quite

OpenStudy (anonymous):

i mean (x-2) )x^2-4x+4)

jimthompson5910 (jim_thompson5910):

hint: in this case, a = x b = 2

OpenStudy (isaiah.feynman):

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