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Mathematics 18 Online
OpenStudy (anonymous):

(Sinx/1-cosx)+(1+cosx/sinx)=2(1+cosx)/(sinx)

OpenStudy (loser66):

the first term: sinx / 1-cosx time both numerator and denominator by 1+ cosx sinx ( 1+ cos x)/ 1- cos^2 x sinx (1+ cos x)/ sin^2x (1+ cosx)/ sinx + the second term = the right hand side

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