Help please?
use upper and lower sums to approximate
the area of the region using the given number of subintervals (of
equal width).
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OpenStudy (anonymous):
OpenStudy (anonymous):
calculator exercise
OpenStudy (anonymous):
?
OpenStudy (anonymous):
How do I do it?
OpenStudy (anonymous):
there are 8 pieces so each are of length \(\frac{1}{4}=.25\)
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OpenStudy (anonymous):
evaluate at \(0,.25,.5,.75,1,1.25,1.5,1.75\) for the lower limit, and multiply it all by \(.25\)
OpenStudy (anonymous):
so here you should look up Riemann summation....must say that is quit annoying question when there is an easier way of finding the area....just google it surely you'll find it
OpenStudy (anonymous):
do I evaluate each at x=2? as in .25 * 2 + .5 *2?
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
or is the width one?
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OpenStudy (turingtest):
the width of each rectangle was told to you by @satellite73 , take the domain of x we are looking at and divide it by the number of rectangles\[2/8=0.25=w\]the height of each rectangle is the y value at a particular x.