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what intervals are continuous y=sqrt(2 - 3x)?
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this is the same question as "what is the domain"
Thats all? and if so, would {x element R : 3 x<=2} be right?
with one tiny difference. the function is not continuous on the half closed interval, but rather on the open interval
also you want to solve for \(x\) not for \(2x\)
\(2-3x>0\) means \(x<\frac{2}{3}\)
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so, which form is correct?
heloo?
Nobody going to answer?
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