Question

proving identities:
(cot+cos)/(sec-cos) = (csc + 1) / tan^2

Answer 1

@Callisto @satellite73

Answer 2

@jagatuba

Answer 3

@dmezzullo

Answer 4

@abb0t

Answer 5

@Loser66 @superdavesuper

Answer 6

@Preetha

Answer 7

@shamil98

Answer 8

\[\text{L.S.}\]\[=\frac{(\cot+\cos)}{(\sec-\cos)}\]\[=\frac{\cot+\cos}{\frac{1}{\cos}-\cos}\]\[=\frac{\cot+\cos}{\frac{1-\cos^2}{\cos}}\]\[=\frac{\cot+\cos}{\sin(\tan)}\]Divide both numerator and denominator by cos\[=\frac{\frac{\cot+\cos}{\cos}}{\tan^2}\]\[=\ ...\]

Answer 9

got it! thank you!! @Callisto

Answer 10

Welcome :)