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how many liters of water must be added to 50 liters of a 30% acid solution in order to produce a 20% acid solution
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Let x be the water added
.30*50 = .20(50 L +x) .30*50 - .20*50 L = .20x .10*50L = .20x 25L = x Hence, 25 liters of water would need to be added
Thank you soooooooooooo much helped alot fan me and ill fan you!
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you're welcome :D
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I was talking to yttrium but thanks any ways!!! :)
Fan me! and ill meadal You!!!! meadl me to
Why did you un fan me :C
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