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Trigonometry
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can anyone help me? (: Find cotθ if θ terminates in Quadrant III and secθ = 2. -root3 -root3/3 root3/3 root3
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|dw:1391150556314:dw|
Let theta = x We know that secx = 1/cosx, that's why were able to do the graph.
|dw:1391150865486:dw| cot x = adjacent/opposite let a = opposite side a = sqrt(2-1) a = -1 cotx = 1 Why it is not in the choices?
I have to go
ummm the answer is in one of the choices probably!
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