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Mathematics 19 Online
OpenStudy (anonymous):

HELP How do I construct the line perpendicular to NO at point P.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (kc_kennylau):

1. c=Circle(center=P, radius=PO) 2. M=IntersectPoint(c,line(NO)) 3. c1=Circle(center=M, radius=MP) 4. c2=Circle(center=O, radius=OP) 5. P1, P2=IntersectPoints(c1, c2) 6. Line(P1,P2)

OpenStudy (kc_kennylau):

Hopefully you'll understand my notation, don't wanna explain it in full text

OpenStudy (anonymous):

I dont understand):

OpenStudy (anonymous):

these were my answer choices

OpenStudy (kc_kennylau):

I suspect it's the third one

OpenStudy (kc_kennylau):

But you deleted them so I can't see at the moment

OpenStudy (anonymous):

OpenStudy (anonymous):

lol sorry i messed up

OpenStudy (anonymous):

but there

OpenStudy (kc_kennylau):

yes it's the third one.

OpenStudy (anonymous):

Thank you (:

OpenStudy (wolf1728):

Okay, putting this into English, place compass point at Point P and measure Line PO. rotating compass 180° strike an arc at point Q. Expanding the compass width to slightly larger than PO, with compass point at Q strike an arc with compass point at O strike an arc the arcs intersect at point R draw perpendicular line RP

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