Question

this is the math of math

Answer 1

\[\sum_{k=1}^{1234}\frac{ kk! }{ 2^k }+\sum_{k=1}^{1234}\frac{ k! }{ 2^k }-\frac{ 1235! }{ 2^{1234}}\] evaluate this

Answer 2

\sum_{k=1}^{1234}\frac{ kk! }{ 2^k }+\sum_{k=1}^{1234}\frac{ k! }{ 2^k }-\frac{ 1235! }{ 2^{1234}}