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antiderivative of ∫(1+x)/(1+x^2).
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try \(u=1+x^2\)
no, that is a bad idea
^ Why?
try \[\frac{1}{1+x^2}+\frac{x}{1+x^2}\] that will work nicely
first is one you do with your eyeballs, (i.e. one you have memorized) second is a mental u - sub
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Oh, I see
sorry, @mkmkasim that was an accident :S
is it arctanx + ln|1+x^2| +c
first is right, second you are off by a constant
how?
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\(u=1+x^2,\frac{1}{2}du=xdx\)
need a \(\frac{1}{2}\) out front to adjust for the u sub
oh okay I got it. Thanks
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