Question

(x^3-27)/(x^2-9)

Answer 1

\[\frac{ x ^{3}-27 }{ x ^{2}-9 }=\frac{x ^{3}-3^{3} }{x ^{2}-3^{2} }=\frac{ \left( x-3 \right)\left( x ^{2}+3x+9 \right) }{ \left( x+3 \right)\left( x-3 \right) }\]
\[=\frac{ x ^{2}+3x+9 }{x+3 }\]