Question

Algebra 2 help?

Answer 1

\( \Huge\frac{ b^{2}-2b-8 }{ b^{2}+b-2 } - \frac{ 6 }{ b-1 } \)

Answer 2

Factor:
\[\frac{ b^{2}-2b-8 }{ b^{2}+b-2 } \implies \frac{b - 4}{b - 1}\]
\[= \frac{b - 4}{b - 1} - \frac{6}{b-1} \implies \frac{b-10}{b-1}\]
Restriction:
\[b \ne 1\]
The denominator cannot be zero.

Answer 3

thanks ;)

Answer 4

No problem :-).