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simplify completely 4x^2- 32x + 48 / 3x^2 - 17x - 6
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Remember to use perenthesis you mean (4x^2- 32x + 48) / (3x^2 - 17x - 6)
factor top (4*(x-2))*(x-6) then bottom (3*x+1)*(x-6)
you'll see what cancels
x-6 will cancel out on the bottom and the top right?
what it really means is "factor and cancel" let me write it so i can read it \[\frac{4x^2- 32x + 48 }{ 3x^2 - 17x - 6}\]
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factors as \[\frac{4(x-2)(x-6)}{(3x+1)(x-6)}\] i guess
oh yeah, you had this already then cancel and you are done
Thanks !
yw, you did all the work
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