9.The size of a television is determined by the length (L) of the screen’s diagonal. The diagram below shows the dimension of a rectangular television screen. On the bottom of the rectangle it's 50 inches and the sides is 33 inches.

To the nearest tenth of an inch, how big is the TV?

Question

9.The size of a television is determined by the length (L) of the screen’s diagonal. The diagram below shows the dimension of a rectangular television screen. On the bottom of the rectangle it's 50 inches and the sides is 33 inches.

To the nearest tenth of an inch, how big is the TV?

***[isuru]*** · Answer

do u know about Pythagoras theorem ?

anonymous · Answer

$$\sqrt{33^2+50^2}$$ and a calculator

anonymous · Answer

Uhhh.....NO lol

anonymous · Answer

I just need the answer and how to get the answer

***[isuru]*** · Answer

|dw:1391205980152:dw|

anonymous · Answer

Here use this link to understand pythagoras theorem & couple of example to solve http://www.mathsisfun.com/pythagoras.html

***[isuru]*** · Answer

and according to the question they've given
   a = 50 
  b = 33

so 
    all u need to find c which is shown by satellite 
          a^2  + b^2 = c^c
        50^2 + 33^2 = c^2
          c^2 = 3589

then c will be the square root of 3589 which is 59 .90

anonymous · Answer

so would the answer be 60 inches

anonymous · Answer

yes by rounding it off

***[isuru]*** · Answer

yep!!

anonymous · Answer

ok thx @annas and @***[ISURU]***