A cylindrical water trough has a diameter of 6 ft and a height of 2 feet. It is being filled at the rate of 4 ft^3/min, so how fast is the water level rising when the water is 1 foot deep?

Question

anonymous · Answer

the radius is 6^2  pi feet. 
it's filling with 4 ft^3/min
$$\large \frac{ 4ft^3 /\min}{ 6^2 \pi ft^2}=0.03537 ft/\min$$

anonymous · Answer

oh wait i messed up the area

anonymous · Answer

$$\large \frac{ 4ft^3 /\min}{ 3^2 \pi ft^2}=0.1415 ft/\min$$

anonymous · Answer

i need fraction form :)

anonymous · Answer

$$\large \frac{ 4 }{ 9 \pi }$$

anonymous · Answer

thank you so much and i have another question like it ok?