Question

Use the Quadratic Formula to solve the equation.

-2x2 - 5x + 5 = 0

Answer 1

\(\bf --2x^2 - 5x + 5 = 0\\
\textit{quadratic formula}\\
\begin{array}{llll}
y=&-2x^2+&-5x+&+5\\
y=&\ ax^2+&\ bx+&c\\
&\uparrow&\uparrow&\uparrow\\
&a&b&c
\end{array}\qquad
x= \cfrac{ - b \pm \sqrt { b^2 -4ac}}{2a}\)

Answer 2

hmm got an extra minus =) \(\bf -2x^2 - 5x + 5 = 0\\
\textit{quadratic formula}\\
\begin{array}{llll}
y=&-2x^2+&-5x+&+5\\
y=&\ ax^2+&\ bx+&c\\
&\uparrow&\uparrow&\uparrow\\
&a&b&c
\end{array}\qquad
x= \cfrac{ - b \pm \sqrt { b^2 -4ac}}{2a}\)

Answer 3

I got \[- \frac{ 5 }{ 2 } \pm \frac{ \sqrt{65} }{ 2 }\]