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State Hooke's law. A spring will stretch 12 cm when a 250-g mass is hung on it. If two springs are hung side by side and both support the 250-g mass, how much will each spring stretch? Explain.
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F = - k x Hooke's law Side-by-side springs each support half the 250g mass so each stretches only half what it would for 250 g, answer: ?
12 x 2 = 24cm
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