Question

Solve the following system of equations.
4x - 2y - z = -5
x - 3y + 2z = 3
3x + y - 2z = -5


a (0, 1, 3)
b (0, -1, 3)
c (0, 1, -3)
d (0, -1, -3)

Answer 1

you can find x from 2nd equation
and put it into others
now now you have 2 variable to find
so can do it again to find y or z
then
put that variable to find other variable , then like that find x

Answer 2

4x - 2y - z = -5
x - 3y + 2z = 3 ---> x=3y-2z+3
3x + y - 2z = -5

4(3y-2z+3)-2y-z=-5
3(3y-2z+3)+y-2z=-5

Answer 3

so -5 would be x?

Answer 4

Sorry its been w while since iv done this.

Answer 5

4(3y-2z+3)-2y-z=-5 12y-8z+12-2y-z=-5
3(3y-2z+3)+y-2z=-5 9y-6z+9+y-2z=-5

10y-9z=-5-12
10y-5z=-5-9

Answer 6

if you try
x=0
y=1
z=3

Answer 7

sorry OS is making my computer freez

Answer 8

freeze*